Problem: Fill array by dice numbers; all different 2

function gapLot(){
  
  var array6=[];
  var array2=[1,2,3,4,5,6];
  var random;
 
    for(var i=0;i<6;i++){ //0-5
      random= Math.floor(Math.random() * (6-i))+1;

        if(random==(6-i)){
   
          array6[i]=array2[5-i];
 
        }else{

  
         array6[i]=array2[random-1];
 
         array2[random-1]=array2[5-i];

  
       }
  }
  
   return array6;
 }
 console.log(gapLot());

Problem: Fill array by dice numbers; all different

 You got array of 6,

 

 It need to be fill dice-numbers all less that 6 more than one. We talk about 1,2,3,4,5,6.  Minimal O is preferred. I mean few loops as possible to do this task.

Here my solution, throw dice, get 6 add that to array

Next acquire smaller dice, 1-5 the d5 throw this now, it show 4

That is not 5, we must remember 5 is 4, so that when we take yet smaller dice, the data not get lost, to help remember what is what, we have a pre-filled array where numbers are in order.

And now 5 is 4 and 4 is 5. The data.

Yes. Then we dice smaller dice d4->

We got a three, next let's update the helper-array, that what is on the position-4 on the helper-array, is 3 and three is that, what have there before(5). So...

D3 ->  1

the helper-array goes:..

To terminate last two numbers we flip coin.