You got array of 6,
It need to be fill dice-numbers all less that 6 more than one. We talk about 1,2,3,4,5,6. Minimal O is preferred. I mean few loops as possible to do this task.
Here my solution, throw dice, get 6 add that to array
Next acquire smaller dice, 1-5 the d5 throw this now, it show 4
That is not 5, we must remember 5 is 4, so that when we take yet smaller dice, the data not get lost, to help remember what is what, we have a pre-filled array where numbers are in order.
And now 5 is 4 and 4 is 5. The data.
Yes. Then we dice smaller dice d4->
We got a three, next let's update the helper-array, that what is on the position-4 on the helper-array, is 3 and three is that, what have there before(5). So...
D3 -> 1
the helper-array goes:..
To terminate last two numbers we flip coin.
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